4. Is rap music more popular among young Indians than among young Asians? A sample survey compared 634 randomly chosen Indians aged 15 to 25 with 567 randomly selected Asians in the same age group. It found that 368 of the Indians and 130 Asians listened to rap music every day. Construct and interpret a 95% confidence interval for the difference between the proportions of Indian and Asian young people who listen to rap every day.

Answer :

Answer:

H0 is accepted

there is no difference between the proportions of Indian and Asian young people who listen to rap music every day.

Step-by-step explanation:

Given  a sample survey compared 634 randomly chosen Indians aged 15 to 25 with 567 randomly selected Asians in the same age group.

[tex]p_{1} = \frac{368}{634} =0.580[/tex]

It found that 368 of the Indians and 130 Asians listened to rap music every day.

[tex]p_{2} = \frac{130}{567} =0.229[/tex]

Null hypothesis H0: there is no difference between the proportions of Indian and Asian young people who listen to rap every day.

[tex]p_{1} = p_{2}[/tex]

Alternative hypothesis:- [tex]p_{1} \neq p_{2}[/tex]

Level of significance α = 0.05

The test of statistic

[tex]z = \frac{p_{1} - p_{2}}{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} }) } } }[/tex]

where [tex]p = \frac{n_{1}p_{1} + n_{1}p_{2}}{n_{1}+n_{2}} = \frac{634(0.580)+567(0.229)}{634+567}[/tex]

       p = 0.414

and q = 1-p = 1- 0.414 =0.586

[tex]Z = \frac{0.580-0.229}{\sqrt{0.414(0.586)(\frac{1}{634} +\frac{1}{567} } } }[/tex]

on calculation , we get

z = 0.300 ><1.96 at 95 % level of significance

H0 is accepted

there is no difference between the proportions of Indian and Asian young people who listen to rap every day.

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