Answer :
Answer: For [tex]F_{2} + H_{2} \rightarrow 2HF[/tex], [tex]F_{2}[/tex] is the oxidizing agent and [tex]H_{2}[/tex] is the reducing agent.
For [tex]2Mg + O_{2} \rightarrow 2MgO[/tex], Mg is the reducing agent and [tex]O_{2}[/tex] is the oxidizing agent.
Explanation:
An oxidizing agent is defined as the substance which tends to oxidize other substances by itself gaining electrons. As a result, there will occur a decrease in its oxidation state.
On the other hand, a substance which tends to reduce other substances by itself losing electrons is known as an reducing agent. There will occur an increase in oxidation state of a reducing agent.
For example, [tex]F_{2} + H_{2} \rightarrow 2HF[/tex]
Oxidation: [tex]H_{2} \rightarrow 2H^{+} + 2e^{-}[/tex]
Reduction: [tex]F + 1e^{-} \rightarrow F^{-}[/tex]
Hence, here [tex]F_{2}[/tex] is the oxidizing agent and [tex]H_{2}[/tex] is the reducing agent.
Also,
[tex]2Mg + O_{2} \rightarrow 2MgO[/tex]
Oxidation: [tex]Mg \rightarrow Mg^{2+} + 2e^{-}[/tex]
Reduction: [tex]O_{2} + 2e^{-} \rightarrow O[/tex]
Hence, here Mg is the reducing agent and [tex]O_{2}[/tex] is the oxidizing agent.