Answer :
Answer:
T₂ = 506.6 K
Explanation:
Given data:
Initial pressure of gas = 25°C (25+273 =298 K)
Initial temperature = 0.500 atm
Final pressure = 0.850 atm
Final temperature = ?
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
0.500 atm / 298 K = 0.850 atm /T₂
T₂ = 0.850 atm × 298 K / 0.500 atm
T₂ = 253.3 atm. K / 0.500 atm
T₂ = 506.6 K