Answer :
Answer:
Wavelength of light used will be equal to 661 nm
Explanation:
We have given distance between slits d = 0.48 mm = [tex]0.48\times 10^{-3}m[/tex]
It is given interference pattern is 3.7 m away so D = 3.7 m
First maximum from the center is 5.1 mm
So [tex]y=5.1\times 10^{-3}m[/tex]
Distance of the first maximum from the center is equal to [tex]y=\frac{\lambda D}{d}[/tex]
[tex]5.1\times 10^{-3}=\frac{\lambda\times 3.7}{0.48\times 10^{-3}}=661\times 10^{-9}=661nm[/tex]
So wavelength of light used will be equal to 661 nm