Answer :
Answer:
total heat required to raise pressure from 2.1 bar to 7.2 bar is 3295.336 kJ
Explanation:
given data
temperature t1 = 33.7°C = 306.7 K
pressure p1 = 2.1 bar
volume v1 = 4.2 m³
pressure p2 = 7.2 bar
ideal gas model k = 1.65
solution
we know heat transfer in constant volume is express as
Q = m × Cv × (t2-t1) .............1
and here gas constant is 208.13 J/Kg.k
specific heat constant volume Cv = [tex]\frac{R}{K-1}[/tex]
put here value
Cv = [tex]\frac{208.13}{1.65-1}[/tex]
Cv = 320.2 J/Kg.k
and
we get mass of argon gas m is
P1 × V1 = m × R × T1
m = [tex]\frac{2.1\times 10^5 \times 4.2}{208.13\times 306.7}[/tex]
m = 13.817 kg
and
t2 = [tex]\frac{7.2\times 306.7}{2.1}[/tex]
t2 = 1051.54 K
and
put equation 1 we get
Q = 13.81 × 320.2 × (1051.54-306.7)
Q = 3295.336 kJ
so total heat required to raise pressure from 2.1 bar to 7.2 bar is 3295.336 kJ