blossomwatson
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What is the standard form equation of the line shown below?

Graph of a line going through negative 2, 3 and 1, negative 3

y + 3 = −2(x − 1)
y = −2x − 1
2x + y = −1
−2x − y = 1

HELP What is the standard form equation of the line shown below? Graph of a line going through negative 2, 3 and 1, negative 3 y + 3 = −2(x − 1) y = −2x − 1 2x class=

Answer :

tarikdahnoun
Standard form means:
Ax+By=C
Where A is the coefficient of x, B is the coefficient of y, and C is the y intercept.

It's true that some of those say the same thing but your answer must be in that form because that is what the question asks. So it should be 2x+y=-1

Answer:

[tex]2x+y=-1[/tex]

Step-by-step explanation:

The given points are

[tex](-2,3)[/tex]

[tex](1,-3)[/tex]

To find the expression of the line shown, first we need to find the slope between the two given points, which the following formula

[tex]m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} } =\frac{-3-3}{1-(-2)}=\frac{-6}{3}=-2[/tex]

Now, we have the slope, then we use the point-slope formula, and replace the slope and one point of the given

[tex]y-y_{1}=m(x-x_{1})\\y-3=-2(x-(-2))\\y=-2x-4+3\\y=-2x-1[/tex]

But, the standard form is like [tex]Ax+Bx=C[/tex]

So,

[tex]2x+y=-1[/tex]

Therefore, the right choice is the third option.

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