Answer:
2 L
Explanation:
Given data:
Initial volume of gas = 2.30 L
Initial temperature = 1.086 atm
Initial temperature = 70°C (70+273 =343 k)
Final volume = ?
Final temperature = standard = 273 K
Final pressure = standard = 1 atm
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
now we will put the values.
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.086 atm ×2.30 L ×273 K / 343 K × 1 atm
V₂ = 681.9 atm.L.K / 343 K . atm
V₂ = 2 L
