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a bag contains 16 red marbles, 7 yellow marbles, and 19 green marbles. how many additional red marbles must be added to the 42 marbles already in the bag so that the probability of randomly drawing a red marble is 3/5

Answer :

Answer:

The number of red marble to be added in box is [tex]23[/tex].

Step-by-step explanation:

Given that,

Number of red marbles  = [tex]16[/tex]

Number of yellow marbles = [tex]7[/tex]  

Number of green marbles = [tex]19[/tex]

Total number of marbles in the bag = [tex]42[/tex]

So,

Let the number of red marbles to be added in bag is [tex]x[/tex].

Then Required probability of random drawing a red marble is [tex]\frac{3}{5}[/tex].

                 [tex]P(E)= \frac{favourable \ outcomes}{total \ number \ of \ outcomes}[/tex]

Here,  New number of red marbles is [tex]16+x[/tex]

And total number of marbles be [tex]42+x.[/tex]

∴                [tex]P(red\ marble) = \frac{16+x}{42+x} =\frac{3}{5}[/tex]

⇒                             [tex]\frac{16+x}{42+x} =\frac{3}{5}[/tex]

Cross- multiplying we get,

⇒                           [tex]5\times (16+x)=3\times (42+x)[/tex]

⇒                            [tex]80+5x=126+3x[/tex]

⇒                                    [tex]2x=46[/tex]

⇒                                     [tex]x=23[/tex]

thus , the new number of marble to be added in bag is [tex]16+23=39[/tex]

And total number of marble in bag become [tex]42+23=65[/tex].

Hence, The number of red marble to be added in box is [tex]23[/tex].

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