An automobile engine provides 639 Joules of work to push the pistons and generates 2194 Joules of heat that must be carried away by the cooling system. Calculate the change in the internal energy of the engine. E = Joules

Answer :

Answer: The change in the internal energy of the engine is - 2833 J

Explanation:

According to first law of thermodynamics:

[tex]\Delta E=q+w[/tex]

[tex]\Delta E[/tex]= Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done by the system= [tex]-P\Delta V[/tex] = -639 J   {Work is done by the system and is negative as the final volume is greater than initial volume }

q = -2194 J   {Heat released by the system is negative}

[tex]\Delta E=-639+(-2194)J=-2833J[/tex]

Thus the change in the internal energy of the engine is - 2833 J

The change in the internal energy of the system (engine) is -2,833 J.

The given parameters;

  • work by the system, w = 639 J
  • heat removed from the system, q = 2194 J

The change in the internal energy of the system (engine) is calculated by applying first law of thermodynamics;

ΔU = q + w

where;

  • q is the heat added to the system
  • w is the work done on the system

ΔU = -(2194 J) + -(639 J)

ΔU = - 2194 J - 639 J

ΔU = -2833 J

Thus, the change in the internal energy of the system (engine) is -2,833 J.

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