Answer :
Answer:
The average field strength is 1.8T
Explanation:
The magnitude of the wire whose length is L carrying a current I and making an angle θ with a magnetic field of density B is calculated using the following formula.
B = F/(I * L * Sin(θ)
Given that F = 2.16N
I = 30 A
L = 4cm = 4 * 10^-2m
θ = π/2
By substitution
B = 2.16/(30 * 4 * 10^-2 * Sin(π/2))
B = 1.8T
Hence, the average field strength is 1.8T
Answer:
the average magnetic field strength is 1.8T
Explanation:
Using the formula to calculate average magnectic field strength
B = F/(I * L * Sin(θ)
re write the above formula
[tex]B = \frac{F}{Il\sin \theta}[/tex]
Given that F = 2.16N
I = 30 A
L = 4cm = 4 * 10^-2m
θ = 90°
substitute the values
[tex]B = \frac{2.16N}{(30.0A)(0.040m)(\sin 90^0)} \\\\B = 1.80T[/tex]
Hence, the average magnetic field strength is 1.8T