Amount in compound interest = p(1 + r/t)^nt where p is the initial
deposit, r = rate, t = number of compunding in a period and n = period.
Here,
Amount after 3 years = 6,800(1 + (5.7/100)/4)^(3 x 4) = 6,800(1 +
0.057/4)^12 = 6,800(1 + 0.01425)^12 = 6,800(1.01425)^12 = 6,800(1.185060) =
$8,058.41
