Answered

A black, totally absorbing piece of cardboard of area a = 2.1 cm2 intercepts light with an intensity of 8.8 w/m2 from a camera strobe light. what radiation pressure is produced on the cardboard by the light?

Answer :

Answer:

The value of radiation pressure is [tex]2.933 \times 10^{-8}[/tex] Pa

Explanation:

Given:

Intensity [tex]I = 8.8[/tex] [tex]\frac{W}{m^{2} }[/tex]

Area of piece [tex]A = 2.1 \times 10^{-4}[/tex] [tex]m^{2}[/tex]

From the formula of radiation pressure in terms of intensity,

   [tex]P = \frac{I}{c}[/tex]

Where [tex]P =[/tex] radiation pressure, [tex]c =[/tex] speed of light

We know value of speed of light,

 [tex]c = 3 \times 10^{8}[/tex] [tex]\frac{m}{s}[/tex]

Put all values in above equation,

  [tex]P = \frac{8.8}{3 \times 10^{8} }[/tex]

  [tex]P = 2.933 \times 10^{-8}[/tex] Pa

Therefore, the value of radiation pressure is [tex]2.933 \times 10^{-8}[/tex] Pa

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