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What is the de Broglie wavelength of a bullet of mass 0.030 kg traveling at 540 m/s? Planck's Constant is 6.63 × 10−34 J⋅s.

4.1 × 10−35 m
3.5 × 10−35 m
2.2 × 10−34 m
1.7 × 10−34 m

Answer :

Answer:

I believe the answer is 4.1 * 10^-35 m

Explanation:

I worked out the problem using the equation for this kind of wavelength.

Since I don't have the special keybind for it, ? will be the wavelength.

? = h/p

In this case, h = Planck's constant, which is 6.63 * 10^-34 J*s.

P = momentum, which is mass * velocity.

M (mass) = 0.030 kg.

V (velocity) = 540 m/s.

0.030 * 540 = 16.2.

P = 16.2

? = h/p

? = (6.63 * 10^-34) / 16.2.

? = 4.0925 * 10^-35.

? = 4.1 * 10^-35.

The wavelength is 4.1 * 10^-35 m.

onyebuchinnaji

The de Broglie wavelength of a bullet of mass of given mass and speed is determined as 4.1 x 10⁻³⁵ m.

Momentum of the mass

The momentum of the mass is calculated as follows;

P = mv

P = 0.03 kg x 540 m/s

P = 16.2 kgm/s

Broglie wavelength of the mass

λ = h/P

λ = (6.63 x 10⁻³⁴) / (16.2)

λ =  4.1 x 10⁻³⁵ m

Thus, the de Broglie wavelength of a bullet of mass of given mass and speed is determined as 4.1 x 10⁻³⁵ m.

Learn more about wavelength here: https://brainly.com/question/10728818

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