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Write the Ksp expression for the sparingly soluble compound calcium fluoride, CaF2. Ksp = If either the numerator or denominator is 1, please enter 1.Write the Ksp expression for the sparingly soluble compound calcium fluoride, CaF2. Ksp = If either the numerator or denominator is 1, please enter 1.

Answer :

Answer: [tex]K_{sp}=\frac{[Ca^{+}][F^{-}]^2}{1}[/tex]

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as

The equation for the ionization of [tex]CaF_2[/tex] the  is given as:

[tex]CaF_2\rightarrow Ca^{2+}+2F^-[/tex]

By stoichiometry of the reaction:

1 mole of [tex]CaF_2[/tex] gives 1 mole of [tex]Ca^{2+}[/tex] and 2 moles of [tex]F^-[/tex]

[tex]K_{sp}=\frac{[Ca^{+}][(F^{-})^2]}{1}[/tex]

Thus [tex]K_{sp}[/tex] of the salt is [tex]\frac{[Ca^{+}][(F^{-})^2]}{1}[/tex]

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