Answered

Which function has real zeros at x = 3 and x = 7?
Of(x) = x2 + 4x - 21
O f(x) = x2 - 4x - 21
Of(x) = x2 - 10x + 21
O f(x) = x2 - 10x – 21

Answer :

jakoh7131
The answer is X2-10X+21

Explanation: If u put the equation in the graphing calculator 3 and 7 both equal zero meaning they are the x’s of the situation.

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