Answer :
Answer:
The angle between the extreme red and extreme violet light in the glass is 1.18°
Explanation:
According the Snell's law:
[tex]n_{a} sin\theta _{a} =n_{b} sin\theta _{b}\\\theta _{b} =sin^{-1} (\frac{n_{a}sin\theta a}{n_{b} } )[/tex]
Where
na = refractive index of air = 1
θa = angle of incidence in air = 66°
For red light nb = 1.61
Replacing:
[tex]\theta _{b} =sin^{-1} (\frac{1*sin66}{1.61} )=34.57[/tex]
For violet light nb = 1.66
[tex]\theta _{b} =sin^{-1} (\frac{1*sin66}{1.66} )=33.39[/tex]
So, the angle between the extreme red and extreme violet light in the glass is 34.57-33.39 = 1.18°
The angle that lies between the extreme red and extreme violet light with respect to the glass should be conisdered as the 1.18°.
Snell law:
Here
[tex]n_a sin_a = n_bsin \theta_b\\\\\theta _b = sin^-1(n_a sin\theta _a)/n_b[/tex]
Here,
na = refractive index of air = 1
θa = angle of incidence in air = 66°
For red light nb = 1.61
So,
[tex]\theta _b = sin^-1(1*sin66)/1.61[/tex]
= 34.57
Now for violet light nb = 1.66
[tex]\theta _b = sin^-1(1*sin66)/1.66[/tex]
= 33.39
So, the angle between should be
= 34.57-33.39
= 1.18 degrees
The following formula should be used for the same.
hence, The angle that lies between the extreme red and extreme violet light with respect to the glass should be conisdered as the 1.18°.
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