Answer:
[tex]\frac{\sqrt{3} }{2}[/tex]
Step-by-step explanation:
sin=opposite/hypotenuse
sin60=[tex]\frac{\sqrt{3} }{2}[/tex]
FAQ:
Why is [tex]\sqrt{3}[/tex] the opposite? That side is the opposite, because the side with length 2 is the hypotenuse. So it can't be that side. Also, side with length 1 is the adjacent side. It's touching. As a result, it's not opposite. This leaves [tex]\sqrt{3}[/tex] as the only side left.
Can it be [tex]\frac{2}{\sqrt{3} }[/tex] instead? No! I'm always surprised by people asking this, but no. You can't switch ANYTHING around for these kind of equations. So please don't try. Also, teachers like to offer the answer to the switched-around equation to trick you. Be confident in your answer.
Hope I could help! Have a braninly day!
Brainliest?
