A pneumatic system is producing 100 lb/in^2 of gauge pressure. A cylinder is needed to press an adhesive label onto a product. It has been determined that 5 lb of force is optimal to complete this task. What is the required diameter of the pneumatic cylinder?

Answer :

lublana

Answer:

0.25 in

Explanation:

We are given that

Pressure,P=[tex]100lb/in^2[/tex]

Force,F=5 lb

We know that

[tex]P=\frac{F}{A}=\frac{F}{\pi\frac{d^2}{4}}[/tex]

Where [tex]A=\frac{\pi d^2}{4}[/tex]

Substitute the values

[tex]100=\frac{5}{\pi\times \frac{d^2}{4}}[/tex]

[tex]\frac{d^2}{4}=\frac{5}{100\pi}[/tex]

[tex]d^2=\frac{5\times 4}{100\pi}[/tex]

[tex]d=\sqrt{\frac{5\times 4}{100\pi}}[/tex]

[tex]d=0.25 in[/tex]

Hence, the diameter of pneumatic cylinder=0.25 in

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