Answer:
The probability that the sum of the numbers rolled will equal 4 is [tex]\frac{1}{12}[/tex]
Step-by-step explanation:
Total possible outcome is 36
The sample space for the dice is shown below
[tex]\left[\begin{array}{cccccc}1,1&1,2&1,3&1,4&1, 5&1,6\\2,1&2,2&2,3&2,4&2, 5&2,6\\3,1&3,2&3,3&3,4&3, 5&3,6\\4,1&4,2&4,3&4,4&4, 5&4,6\\5,1&5,2&5,3&5,4&5, 5&5,6\\6,1&6,2&6,3&6,4&6, 5&6,6\end{array}\right][/tex]
From the above sample, the event of sum equals 4 is:
(1, 3)
(2, 2)
(3, 1)
Number of outcome with sum equals 4 is 3
[tex]Probability = \frac{number of possible outcome}{number of total outcome} \\Probability = \frac{3}{36} = \frac{1}{12}[/tex]
The probability that the sum of the numbers rolled will equal 4 is [tex]\frac{1}{12}[/tex]
Answer:
0.3333
Step-by-step explanation:
Out of 6x6 = 36 different scenarios that could happen when rolling the 2 cubes, there are 3 cases where the sum of the numbers rolled will equal 4:
(1,3) (3,1) and (2,2)
So the probability for these 3 cases to happen out of 36 is
[tex]\frac{3}{36} = \frac{1}{3}[/tex] or 0.3333
