kyledove39
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The Sharpeville demonstration of 1960 resulted in
the deaths of sixty-nine people.
the arrest of a famous leader.
the Population Registration Act.
the creation of segregated societies.

Answer :

PunIntended

Answer:

A

Explanation:

The Sharpeville demonstration of 1960, also known as the Sharpeville Massacre, occurred in Sharpeville, South Africa, as a result of a protest against pass laws, which were basically a set of legislations that were designed to segregate the population into blacks and whites.

About 7000 protesters gathered at a police station, and the police officers panicked, accidentally setting off their firearms. The grim result was that 69 people were killed and many more were injured.

Hope this helps!

Lanuel

The Sharpeville demonstration of 1960 is an event which resulted in: A. the deaths of sixty-nine people.

What is the Sharpeville demonstration of 1960?

Sharpeville demonstration of 1960 was a political, social and civil rights protest that was organized by Black South Africans against apartheid in South Africa such as government's restriction of non-white travel (pass laws).

On the 21st of March, 1960 in the Black township of Sharpeville, police officers fired at this group of peaceful protesters which to led to the death of sixty-nine (69) people while one-hundred and eighty (180) injured.

Read more on Sharpeville demonstration here: https://brainly.com/question/1128568

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