Answer :
Answer:
d) A two-sample z-interval for a difference in sample proportions
Step-by-step explanation:
Explanation:-
Given data a random sample of 40 engines of one design, 14 failed to ignite as a result of fuel system error.
First sample proportion [tex]p_{1} = \frac{14}{40} = 0.35[/tex]
Given data random sample of 30 engines of a second design, 9 failed to ignite as a result of fuel system error.
second sample proportion [tex]p_{2} = \frac{9}{30} = 0.30[/tex]
Null hypothesis: H₀: Assume that there is no significant between the two designs
H₀: p₁ = p₂
Alternative Hypothesis: H₁:
H₁: p₁ ≠ p₂
The test statistic
[tex]Z = \frac{p_{1}-p_{2} }{\sqrt{p q(\frac{1}{n_{1} } + \frac{1}{n_{2} } } )}[/tex]
where [tex]p = \frac{n_{1} p_{1}+n_{2} p_{2} }{n_{1} +n_{2} }[/tex]
q =1-p
Answer:
E
Step-by-step explanation:
A two-sample z-interval for a difference in population proportions