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Point O is the center of the circle. Circle O is shown. Tangents D C and B C intersect at point C outside of the circle. Lines are drawn from points D and point B to center point O to form a quadrilateral. A line is drawn from point C to point A on the opposite side of the circle. The length of O D is 6, and the length of B C is 8. Angles D and B are right angles. What is the perimeter of quadrilateral DOBC?

Answer :

langnewman

Answer:

The perimeter is 28 (6 plus 8=14 14x2= 28)

Step-by-step explanation:

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akposevictor

The perimeter of quadrilateral DOBC that forms two right triangles is: 28 units.

What are Congruent Right Triangles?

Based on the tangent theorem, triangles ODC and OBC are right triangles that are congruent. Therefore, their corresponding side lengths are equal.

Perimeter of quadrilateral DOBC = OB + DO + BC + CD = 6 + 6 + 8 + 8

Perimeter of quadrilateral DOBC = 28 units.

Learn more about congruent right triangles on:

https://brainly.com/question/1675117

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