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2. A two-stage rocket is in development. The required probability is for the overall rocket to be a minimum of 97% reliable for a successful mission. The first stage is a previously developed design with a known reliability of 99%. The reliability measures for the two stages are independent. What must the minimum reliability for the second stage be

Answer :

Answer: The minimum reliability for the second stage be 0.979.

Step-by-step explanation:

Since we have given that

Probability for the overall rocket reliable for a successful mission = 97%

Probability for the first stage = 99%

We need to find the minimum reliability for the second stage :

So, it becomes:

P(overall reliability) = P(first stage ) × P(second stage)

[tex]0.97=0.99\times x\\\\\dfrac{0.97}{0.99}=x\\\\0.979=x[/tex]

Hence, the minimum reliability for the second stage be 0.979.

Using probability of independent events, it is found that the minimum reliability for the second stage must be of 97.98%.

If two events, A and B, are independent, the probability of both events happening is the multiplication of the probability of each happening, that is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

In this problem:

  • There are 2 stages, A and B.
  • The first stage is 99% reliable, hence [tex]P(A) = 0.99[/tex].
  • The system has to be 97% reliable, hence [tex]P(A \cap B) = 0.97[/tex].

Then:

[tex]P(A \cap B) = P(A)P(B)[/tex]

[tex]0.97 = 0.99P(B)[/tex]

[tex]P(B) = \frac{0.97}{0.99}[/tex]

[tex]P(B) = 0.9798[/tex]

Hence, the minimum reliability for the second stage must be of 97.98%.

A similar problem is given at https://brainly.com/question/24174994

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