Answer :
Answer:
= 0.0021
Since this probability is less than 0.05,
Yes , it is unusual to see 32% who really or never use academic advising services.
Explanation:
Given,
Standard error = Sqrt( p( 1 -p) / n) = 0.035
Using normal approximation,
P( p<= p ) = P( Z < p - p / Sqrt( p( 1 -p) / n) )
= P( Z <= 0.32 - 0.42 / 0.035)
= P( Z < -2.8571)
= 1 - P( Z < 2.8571)
= 1 - 0.9979
= 0.0021
Since this probability is less than 0.05,
Yes , it is unusual to see 32% who really or never use academic advising services.