Answer :
Answer:
We have
[tex]\frac{x^2-9}{x^2+2x-15}[/tex]
[tex]\frac{\left(x+3\right)\left(x-3\right)}{x^2+2x-15}[/tex]
[tex]\frac{\left(x+3\right)\left(x-3\right)}{\left(x-3\right)\left(x+5\right)}[/tex]
[tex]\frac{x+3}{x+5}[/tex]
∴The answer is D