Answer :
[tex]f(x)=5x+9\\
f'(x)=5[/tex]
The derivative is constant. It's equal 5 for any argument.
[tex]f(x)=\dfrac{6}{x}\\ f'(x)=-\dfrac{6}{x^2}\\ f'(-2)=-\dfrac{6}{(-2)^2}=-\dfrac{6}{4}=-\dfrac{3}{2}[/tex]
The derivative is constant. It's equal 5 for any argument.
[tex]f(x)=\dfrac{6}{x}\\ f'(x)=-\dfrac{6}{x^2}\\ f'(-2)=-\dfrac{6}{(-2)^2}=-\dfrac{6}{4}=-\dfrac{3}{2}[/tex]