Answer :

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Answer:

  • 609g

Explanation:

The translated question is:

What maximum amount of grams of potassium nitrate (V) can be dissolved in 300g of water at 90 °C

Solution

To answer the question you need to consultate the solubiity information for potassium nitrate (V), KNO₃.

The attached table contains the solutibility table for KNO₃ at different temperatures.

At 90ºC it is 203g / 100g water.

Then, to calculate the maximum amount of grams of potassium nitrate (V) that can be dissolved in 300g of water at 90 °C, just multiply by the amount of water:

  • 203g / 100g water × 300 g water = 609g ← answer
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