Answer :
Answer:
[tex]p_2=347.9kPa[/tex]
Explanation:
Hello,
In this case, we use the Gay-Lussac's law which allows us to understand a gas' pressure-temperature behavior as a directly proportional relationship:
[tex]\frac{p_1}{T_1}= \frac{p_2}{T_2}[/tex]
Whereas it is convenient to use the pressure in kPa and the temperature in kelvins in order to compute the required resulting pressure, therefore:
[tex]p_1=55.0psi*\frac{6.89476kPa}{1psi} =379.2kPa\\T_1=30.0+273.15=303.15K\\T_2=5.0+273.15=278.15K[/tex]
Thus, we obtain:
[tex]p_2= \frac{p_1T_2}{T_1}=\frac{379.2kPa*278.15K}{303.15K}\\ \\p_2=347.9kPa[/tex]
Best regards.
Answer:
The pressure in the tire at 5.0 °C is 347.91 kPa
Explanation:
Step 1: Data given
The pressure in a bicycle tire is 55.0 psi
Temperature = 30.0 °C = 303 K
Temperature decreases to 5.0 °C = 278 K
Volume and Amount of moles are held constant
Step 2: Calculate the pressure at the new temperature
P1/T1 = P2 / T2
⇒with P1 = the initial pressure of the bicycle tire is 55.0 psi
⇒with T1 = the initial temeprature = 303 K
⇒with P2 = the pressure at the new temperature
⇒with T2 = the decreased temperature = 278 K
55.0 psi / 303 K = P2 / 278 K
P2 = (55.0 psi / 303 K) * 278 K
P2 = 50.46 psi
Step 3: Convert pressure from psi to kPa
50.46 psi = 50.46 * 6.895 = 347.91 kPa
The pressure in the tire at 5.0 °C is 347.91 kPa