3. Graph the following line 3x – 4y +12 = 0
(put in y=mx+b form first)
PLS HELP ME

Answer:
The answer to your question is below
Step-by-step explanation:
Data
Line: 3x - 4y + 12 = 0
Process
1.- Subtract 3x in both sides
3x - 4y - 3x + 12 = -3x
2.- Simplify
- 4y + 12 = -3x
3.- Subtract 12 in both sides
-4y + 12 - 12 = -3x - 12
4.- Simplify
-4y = -3x - 12
5.- Divide by -4 both sides
-4y/-4 = -3x/-4 - 12/-4
6.- Simplify
y = 3/4x + 3
7.- Graph y-intersept (3)
8.- From the number three, count trhee units up and four units to the right (3/4).
9.- Join the points
Answer:
y= 3/4x + 3 (-8, -3) (-4, 0) (0, 3) (4, 6) (8, 9)
Step-by-step explanation:
for y=mx+b form
1. move the expression to the right and change its sign
-4y= -3x - 12
2. change the signs on both sides of the equation
4y= 3x+12
3. divide both sides by 4
y= 3/4x + 3
for graphing
1. plot a point at 3 on the y line ( this is your y intercept y=3/4x +3) (0, 3)
2 From there go up 3 on the y line and then go over 4 to the right you should end up at (4, 6)
3 continue repeating this step until you have at least 4 points plotted. the next point should be at (8, 9)
4 you can also go down instead of up. from point 3 on the y line, go down 3 and over to the left 4, you should end up at ( -4, 0) the next point down would be (-8, -3)