Answer :
3x^2-2x+7=0
3x^2-2x=-7
3(x^2-2/3x)=-7
3(x^2-2/3x+1/9)=-7+3*(1/9)
3(x^2-2/3x+1/9) = -20/3
3(x-1/3)^2 = -20/3
(x-1/3)^2 = (-20/3)/3
(x-1/3)^2 = -20/9
3x^2-2x=-7
3(x^2-2/3x)=-7
3(x^2-2/3x+1/9)=-7+3*(1/9)
3(x^2-2/3x+1/9) = -20/3
3(x-1/3)^2 = -20/3
(x-1/3)^2 = (-20/3)/3
(x-1/3)^2 = -20/9