Answer :
Answer : The new pressure if the sample placed in a 2.00-L container is, 0.494 atm.
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
[tex]P\propto \frac{1}{V}[/tex]
or,
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure = 0.988 atm
[tex]P_2[/tex] = final pressure = ?
[tex]V_1[/tex] = initial volume = 1.00 L
[tex]V_2[/tex] = final volume = 2.00 L
Now put all the given values in the above equation, we get:
[tex]0.988atm\times 1.00L=P_2\times 2.00L[/tex]
[tex]P_2=0.494atm[/tex]
Thus, the new pressure if the sample placed in a 2.00-L container is, 0.494 atm.
The new pressure if the sample is placed in a 2.00-L container is 0.494 atm.
Boyle's Law:
It means the pressure of the gas should be inversely proportional with respect to the volume of the gas at the same temperature also the no of moles.
P1V1 = P2V2
Here
P1 = initial pressure = 0.988 atm
P2 = final pressure = ?
V1 = initial volume = 1.00 L
V2 = final volume = 2.00 L
So,
the new pressure should be
0.988 * 1.00L = P2 * 2.00l
So, P2 is 0.494 atm
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