Answer :
Answer:
A. The moles of H(aq) equal the moles of OH
Explanation:
Thats what my chemistry teacher said Just trying to help out since theres no other answers.
10.0 mL, 0.50 M [tex]H_2SO_4[/tex] will completely neutralize 5.0 mL, 2.0 M NaOH because the moles of each reactant balance one another
Mole ratios
According to the equation of the reaction:
[tex]H_2SO_4 + 2NaOH ---- > Na_2SO_4 +2H_2O[/tex]
The mole ratio is 1:2. Thus NaOH must have twice the number of moles of [tex]H_2SO_4[/tex] for neutralization to take place.
Mole of 10 mL, 0.5 M [tex]H_2SO_4[/tex] = 0.001 x 0.5 = 0.005 moles
Mole of 5 mL, 2 M NaOH = 0.005 x 2 = 0.01 moles
Thus, the moles of NaOH is greater than that of [tex]H_2SO_4[/tex].
More on stoichiometric calculations can be found here: https://brainly.com/question/27287858
#SPJ2