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Consider a population of flowers in which two stem types are observed, tall and short. Tall is dominant to short. After monitoring this population closely for 10 generations, it is determined that the allele frequency for T is 0.35 and the allele frequency for t is 0.65 and it has not changed within the observation period. If you assume that Hardy-Weinberg equilibrium estalished, indicate the expected frequency of each genotype based on the equation for Hardy-Weinberg equilibrium. The equation for Hardy-Weinberg equilibrium states that at a locus with two alleles, as in this flower population, the three genotypes will occur in specific proportions: p2 + 2pq + q2 = 1 (Answers must be provided with the hundredth of a point. Round up on values of 5 or greater, if necessary.) What is the genotype frequency for TT plants? What is the genotype frequency for Tt plants? What is the genotype frequency for tt plants?

Answer :

Answer:

Frequency of homozygous TT individual  [tex]= 0.1225[/tex]

Frequency of homozygous tt individual  [tex]= 0.4225[/tex]

Frequency of homozygous Tt individual [tex]= 0.455[/tex]

Explanation:

Given

Tall (T)  is dominant to short (t)

Allele frequency (p) of dominant allele "T" [tex]= 0.35[/tex]

Allele frequency (q) of recessive allele "t" [tex]= 0.65[/tex]

Frequency of homozygous TT individual

[tex]p^2 = 0.35^2\\p^2 = 0.1225[/tex]

Frequency of homozygous tt individual

[tex]q^2 = 0.65^2\\q^2 = 0.4225[/tex]

As per Hardy Weinberg's second equilibrium equation -

[tex]p^2 + q^2 + 2pq = 1\\[/tex]

Substituting the value of [tex]p^2[/tex] and [tex]q^2[/tex] we get -

[tex]0.1225 + 0.4225 + 2pq = 1\\2pq = 1 - (0.1225 + 0.4225)\\2pq = 0.455[/tex]

Frequency of homozygous TT individual  [tex]= 0.1225[/tex]

Frequency of homozygous tt individual  [tex]= 0.4225[/tex]

Frequency of homozygous Tt individual [tex]= 0.455[/tex]

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