Answer:
[tex] x = 9 \sqrt{10} [/tex]
Step-by-step explanation:
By Geometric mean property:
[tex]y = \sqrt{3 \times 27} \\ = \sqrt{81} \\ y = 9 \\ by \: pythagors \: theorem : \\ x = \sqrt{ {27}^{2} + {9}^{2} } \\ = \sqrt{(9 \times 3)^{2} + {9}^{2} } \\ = \sqrt{ {9}^{2} \times {3}^{2} + { {9}^{2} } } \\ = \sqrt{ {9}^{2} ( {3}^{2} + 1)} \\ = 9 \sqrt{9 + 1} \\ x = 9 \sqrt{10} [/tex]
