Answer :
Answer:
The final temperature of the ice is [tex]-40^{\circ}\ C[/tex].
Explanation:
It is given that,
Energy, Q = 10 cal
Mass of ice, m = 2 g
Initial temperature, [tex]T_1=-30^{\circ}\ C[/tex]
We need to find the final temperature of the ice. We know that the specific heat of ice is [tex]0.5\ cal\ g^{-1} ^{\circ} C^{-1}[/tex]
The heat added in terms of specific heat is given by :
[tex]Q=mc(T_1-T_2)[/tex]
[tex]T_2[/tex] final temperature of the ice
c is specific heat of ice
[tex]T_2=T_1-\dfrac{Q}{mc}\\\\T_2=(-30)-\dfrac{10}{2\times 0.5}\\\\T_2=-40^{\circ}[/tex]
So, the final temperature of the ice is [tex]-40^{\circ}\ C[/tex].