vickyy2
Answered

Suppose a normal distribution has a mean of 79 and a standard deviation of 7. What is P(x > or = to 86)?

Answer :

mysticchacha

Answer:

P(X >= 86) =  P (Z  >= 1) = 0.1587 from the Z-scores table

Step-by-step explanation:

Hopefully this time I will not make an algebraic mistake.

Ok

so  mean u = 79,  and standard dev = s = 7

We want P(X >= 86)

Standardize:

P ( (X - u)/s  >=  (86 - 79)/7 ) =  P (Z  >= 1) = 0.1587 from the Z-scores table

ck247730

Answer to your question is 0.16

Explanation xepA

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