A veterinarian surveys her clients and finds that 32 percent of the households have dogs, 25 percent have cats, and 11 percent have both dogs and cats. Let event C be choosing a client who has cats and let event D be choosing a client who has dogs. Which statements are true? Check all that apply.
P(C | D) = 0.78
P(D | C) = 0.44
P(C ∩ D) = 0.11
P(C ∩ D) = P(D ∩ C)
P(C | D) = P(D | C)

Question

delacruzandrea2005 delacruzandrea2005

Today at 4:11 PM
Mathematics

Answered

A veterinarian surveys her clients and finds that 32 percent of the households have dogs, 25 percent have cats, and 11 percent have both dogs and cats. Let event C be choosing a client who has cats and let event D be choosing a client who has dogs. Which statements are true? Check all that apply.
P(C | D) = 0.78
P(D | C) = 0.44
P(C ∩ D) = 0.11
P(C ∩ D) = P(D ∩ C)
P(C | D) = P(D | C)

Answer :

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loganscantlan loganscantlan · Answer 1 · 2025-03-30T16:16:20-04:00

loganscantlan loganscantlan

Today at 4:16 PM

Answer:

B C D

Step-by-step explanation:

ED 2020

Answer Link

kaitlinsierras kaitlinsierras · Answer 2 · 2025-03-30T16:16:16-04:00

kaitlinsierras kaitlinsierras

Today at 4:16 PM

Answer:

B: P(D | C) = 0.44

C: P(C ∩ D) = 0.11

D: P(C ∩ D) = P(D ∩ C)

next is C: 2/9

then C: P(Y | X) = P(Y)

and F: P(X | Y) = P(X)

next is

10/26

5/14

not independent

Step-by-step explanation:

edg2021

Answer Link