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A bag contains 4 red marbles, 3 blue marbles and 2 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that both marbles drawn will be red?

Answer :

leena

Answer:

≈19.7%

Step-by-step explanation:

To solve this, we first need to find the probability of drawing one red marble. You can do this by adding up all of the marbles and deriving a fraction of red marbles which would get you:

Probability of red= [tex]\frac{4}{9}[/tex]

To find the probability of drawing red 2 times, you will simply need to multiply:

[tex]\frac{4}{9}[/tex] ×[tex]\frac{4}{9}[/tex]= [tex]\frac{16}{81}[/tex]

To convert this to a percent, you can simply divide...

16÷81≈0.197

...And then multiply by 100.

0.197×100= 19.7%

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