Answer :

Answer:

1.53 L.

Explanation:

Given,

Volume pf hydrogen, V₁ = 153.48 mL = 0.15348 L

Temperature, T₁ = 14°C = 273+14 = 287 K

Pressure,P₁ = 973 kPa

1 atm = 101.325 kPa

973 kPa = 9.60 atm

At STP

P₂ = 1 atm

T₂ = 25° C = 273+25 = 298 K

V₂ = ?

Now,

[tex]\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

[tex]\dfrac{9.60\times 0.15348}{287}=\dfrac{1\times V_2}{298}[/tex]

[tex]V_2 = 1.53\ L[/tex]

Hence, the volume at STP is 1.53 L.

Other Questions