Answer :
Answer:a
Explanation:
Given
[tex][H^+]=5.3\times 10^{-4}\ M[/tex]
and [tex]pH+pOH=14[/tex]
Also [tex]pH=-\log [H^+][/tex]
therefore [tex]pH=-\log (5.3\times 10^{-3})[/tex]
[tex]pH=-(-4-\log (5.3))[/tex]
[tex]pH=3.275[/tex]
Thus [tex]pOH=14-3.275[/tex]
[tex]pOH=10.275[/tex]
and [tex]pOH=-\log [OH^{-}][/tex]
[tex][OH]^{-1}=10^{-10.25}[/tex]
[tex][OH]^{-1}=1.88\times 10^{-11}\ M[/tex]
As the pH is less than 7 therefore solution is acidic