Answer :
Answer:A
Step-by-step explanation: 14% of the mothers work part-time in families where the father works part-time while 7% of the mothers work part-time in families where the father is not working.
Probabilities are used to determine how likely or unlikely an event is. From the 2-column table, it is twice as likely to get a family where the father and the mother work part-time than a family where the father doesn't work, and the mother works part-time.
We use the following representation:
[tex]FF \to[/tex] Father works full-time
[tex]FP \to[/tex] Father works part-time
[tex]FW \to[/tex] Father not working
[tex]MF \to[/tex] Mother works full-time
[tex]MP \to[/tex] Mother works part-time
[tex]MW \to[/tex] Mother not working
Next, we test each of the 4 options, till one of the options is true (see attachment)
Choice A:
The claim in choice A is that:
[tex]P(FP\ and\ MP) = 2 \times P(FW\ and\ MP)[/tex]
From the given table, we have:
[tex]P(FP\ and\ MP) = 0.14[/tex] ---- father works part-time and mother works part-time
[tex]P(FW\ and\ MP) =0.07[/tex] ---- father not working and mother works part-time
Put the above values in the following equation
[tex]P(FP\ and\ MP) = 2 \times P(FW\ and\ MP)[/tex]
[tex]0.14 = 2 \times 0.07[/tex]
[tex]0.14 = 0.14[/tex]
The above equation is true.
Hence, choice (A) is true
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