Answer :
Answer:
Explanation:
Problem relates to diffraction of light . Location for 2 nd diffraction minima is
[tex]x=2\times\frac{\lambda D}{d}[/tex] where λ is wavelength of light , D is distance of screen , d is slit width .
Puting the values
[tex]x=2\times\frac{620D}{d}[/tex]
for unknown wavelength , position of third diffraction is
[tex]x=3\times\frac{\lambda D}{d}[/tex]
from these two equations
[tex]x=2\times\frac{620D}{d}[/tex][tex]=3\times\frac{\lambda D}{d}[/tex]
λ = 413.33 nm .