Answer :
Answer:
80
Step-by-step explanation:
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The intensity of the sound when I =10^8(I₀) is 80 dB.
Equation for intensity of sound
The equation for the intensity of sound is given as I(dB)=10log[I/I₀],
where;
- I is the intensity of a given sound
- I₀ is the threshold of a hearing intensity
The intensity when I =10^8(I₀) is calculated as follows;
[tex]I(dB) = 10log[\frac{I}{I_o} ][/tex]
when I = 10^8(I₀)
[tex]I(dB) = 10log [\frac{10^8 \times I_o}{I_o} ]\\\\I(dB) = 10 log[10^8]\\\\I(dB) = (10 \times 8) log10\\\\I(dB) = 80[/tex]
Thus, the intensity of the sound when I =10^8(I₀) is 80 dB.
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