Answer :

janharder
1.

f(x) =-2x^2+12x+1

f'(x) =-4x+12

0=-4x+12

-12=-4x

3=x


Highest value at x=3

f(3)= - 2*3^2+12*3+1
f(3)=-18+37
=19


Maximum value =19


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