Answer :
Answer:
[tex] \mu_{\bar X} = 90[/tex]
[tex] \sigma_{\bar X} =\frac{\sigma}{\sqrt{n}}= \frac{9.6}{\sqrt{144}}= 0.8[/tex]
Step-by-step explanation:
For this case we have a population with the following parameters:
[tex]\mu = 90, \sigma =9.6[/tex]
For this case we have a sample of n= 144 and this sample size is larger (>30) then we can apply the central limit theorem and the distirbution for the sample mean is given by:
[tex] \bar X \sim N( \mu, \frac{\sigma}{\sqrt{n}}) [/tex]
And replacing we got:
[tex] \mu_{\bar X} = 90[/tex]
And the standard deviation is given by:
[tex] \sigma_{\bar X} =\frac{\sigma}{\sqrt{n}}= \frac{9.6}{\sqrt{144}}= 0.8[/tex]
Answer:
μx = 80, σx = 0.52
Step-by-step explanation:
I took the quiz and got it right