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Find the median of the data in the box plot below.


kg
kgstart text, k, g, end text
A horizontal boxplot titled Masses of Farmer Faye's pumpkins, in kilograms, is plotted along a horizontal axis marked from 2 to 10, in increments of 0.5. A left whisker extends from 4.5 to 6. The box extends from 6 to 8.5 and is divided into 2 parts by a vertical line segment at 7. The right whisker extends from 8.5 to 10. All values estimated.

Answer :

cchilabert

Answer:

Median = 7 kg

Step-by-step explanation:

Hello!

To construct a box plot you have to follow the steps:

1) identify the 1st quartile (it represents the lower limit of the box)

2) identify the 3rd quartile (it represents the upper limit of the box)

3) Identify the 2nd quartile or median, as you know it separates the bottom 50% of the data distribution from the top 50%. You'll always find it represented by a line within the two limits of the box.

4) Identify the minimum value. The left or lower whisker is extended from the 1st quartile to the minimum value.

5) Identify the maximum value. The right or upper whisker is extended from the 3rd quartile to the maximum value.

In this example, the lower limit of the box is 6 and the upper limit is 8.5, within the box you find the median is represented by a vertical line at 7

Q1= 6 kg

Q2/ Median= 7 kg

Q3= 8.5 kg

(Sketch in attachment)

I hope this helps!

${teks-lihat-gambar} cchilabert

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