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Using the balanced chemical equation; how many moles of ammonia will
be made if 12g of hydrogen gas is reacted with excess nitrogen?
(Remember Hydrogen gas is diatomic) *
N2 + 3 H2 → 2 NH3 (AH = -92.4 kJ.mol-1)
8 moles
6 moles
4 moles
2 moles

Answer :

dsdrajlin

Answer:

4 moles

Explanation:

Step 1: Write the balanced equation

N₂ + 3 H₂ → 2 NH₃ (ΔH = -92.4 kJ.mol⁻¹)

Step 2: Calculate the moles of hydrogen

The molar mass of H₂ is 2.0 g/mol. The moles corresponding to 12 grams are:

[tex]12g \times \frac{1mol}{2.0g} =6.0mol[/tex]

Step 3: Calculate the moles of ammonia

The molar ratio of H₂ to NH₃ is 3:2. The moles of ammonia produced from 6.0 moles of hydrogen are:

[tex]6.0molH_2 \times \frac{2molNH_3}{3molH_2} =4 molNH_3[/tex]

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