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In the reaction NO + NO2 ⇌ N2O3, an experiment finds equilibrium concentrations of [NO] = 3.8 M, [NO2] = 3.9 M, and [N2O3] = 1.3 M. What is the equilibrium constant Kc for this reaction?

Answer :

Answer: The equilibrium constant [tex]K_c[/tex] for this reaction is 0.088

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]

For the given chemical reaction:

[tex]NO+NO_2(g)\rightarrow N_2O_3[/tex]

The expression for [tex]K_c[/tex] is written as:

[tex]K_c=\frac{[N_2O_3]}{[NO_2][NO]}[/tex]

[tex]K_c=\frac{(1.3)}{(3.9)\times (3.8)}[/tex]

[tex]K_c=0.088[/tex]

The equilibrium constant [tex]K_c[/tex] for this reaction is 0.088

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