Answer :
Answer:30 cm
Explanation:
Given
object distance [tex]u=30\ cm[/tex]
focal length of concave mirror [tex]f=15\ cm[/tex]
height of object [tex]h_o=1.8\ cm[/tex]
Using mirror formula
[tex]\Rightarrow \frac{1}{v}+\frac{1}{u}=\frac{1}{f}[/tex]
[tex]\Rightarrow \frac{1}{v}=\frac{1}{15}-\frac{1}{30}[/tex]
[tex]\Rightarrow \frac{1}{v}=\frac{2-1}{30}[/tex]
[tex]\Rightarrow v=30\ cm[/tex]
and magnification is
[tex]\Rightarrow m=\frac{-v}{u}=\frac{h_i}{h_o}[/tex]
[tex]\Rightarrow \frac{-30}{30}=\frac{h_i}{1.8}[/tex]
[tex]\Rightarrow h_i=-1.8\ cm[/tex]
So height of object is same as of object .
Position :image is formed at the spot where object is placed.