Answer :
Answer:
[tex]\lambda=3.64\times 10^{-12}\ m[/tex]
Explanation:
We have,
Speed of an electron is [tex]2\times 10^8\ m/s[/tex]
It is required to find the De Broglie wavelength of electron. The formula for the De- Broglie wavelength is given by :
[tex]\lambda=\dfrac{h}{mv}[/tex]
h is Planck's constant
m is mass of an electron
Plugging all the values we get :
[tex]\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^{8}}\\\\\lambda=3.64\times 10^{-12}\ m[/tex]
So, the De-Broglie wavelength of an electron is [tex]3.64\times 10^{-12}\ m[/tex]